Flower Bouquets - Coding Question DP
Flower Bouquets
Lara owns a flower shop where she sells only two types of flower bouquets:
- Type 1: The first type of bouquet contains three roses and costs p dollars.
- Type 2: The second type of bouquet contains one cosmos and one rose and costs q dollars.
Lara grows these flowers in her own garden in a single row. Consider the row as a one-dimensional array where each cell either contains a rose or a cosmos. For example, in the array 001101011
, 0
indicates a rose and 1
indicates a cosmos.
Lara follows an important rule when she makes the bouquets: she makes each bouquet with only consecutive flowers from the array. For example, in a bouquet, the flowers from consecutive indices (i,i+1,i+2)(i, i+1, i+2)(i,i+1,i+2) in the array can be present, but not from non-consecutive indices (i,i+2)(i, i+2)(i,i+2). In the array above, Lara cannot make any bouquets of type 1 but she can make 3 bouquets of type 2.
Now she wonders what is the maximum profit she can make if she makes these bouquets optimally. You are given a binary string representing her garden row. Calculate the maximum profit Lara can make. Remember that it is not necessary to use every flower.
Function Description
Complete the flowerBouquets
function in the editor below. The function must return an integer that denotes the maximum profit Lara can make if she makes her bouquets optimally.
flowerBouquets
has three parameters:
p
: integer denoting the cost of a bouquet of type 1.q
: integer denoting the cost of a bouquet of type 2.s
: string denoting the garden pattern, where zero indicates rose and one indicates cosmos.
Constraints
- 1≤p,q≤1000
- 1≤ mod(s) ≤ 100000
Input Format For Custom Testing
Sample Case 0
Sample Input 0
1
2
3
2
3
0001000
Sample Output 0
1
5
Explanation 0
Lara can make two bouquets of three roses by the corresponding indices: (0,1,2)(0, 1, 2)(0,1,2) and (4,5,6)(4, 5, 6)(4,5,6) and can earn 2+2=42 + 2 = 42+2=4 profit.
Or,
Lara can make one bouquet of three roses by the corresponding indices: (0,1,2)(0, 1, 2)(0,1,2) and one bouquet of one rose and one cosmos by the corresponding indices (3,4)(3, 4)(3,4) and can earn 2+3=52 + 3 = 52+3=5 profit.
5 is greater than 4 so print 5.